Physics Question: Kinematics Please show your work!?


A truck driving at 35 m/s can decelerate at a maximum of -3.25 m/s^2. If the driver sees a barrier 150 m ahead of him, can he stop in time?

use the equation

v² = u² + 2as

where
v = final velocity
u = initial velocity
a = constant acceleration
s = distance

s = (v² – u²) / 2a

s = (0² – 35²) / 2(-3.25)
s = 188 m

as this distance is greater than 150 m, a collision with the barrier is unavoidable if steering around the barrier is not an option.

I hope this helps.
Please remember to select a “Best Answer” from among your results, It’s good karma as it helps keep the exchange in balance.

Here are the 4 equations you need to know for kinematics.

http://www.physicsclassroom.com/class/1D…

Find d. If it’s less than 150 m, the truck driver can stop in time.

Leave a Reply

Your email address will not be published. Required fields are marked *